(x-4)^2=(x-6)(x-1)

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Solution for (x-4)^2=(x-6)(x-1) equation: 



(x-4)^2=(x-6)(x-1)

We move all terms to the left:

(x-4)^2-((x-6)(x-1))=0

We multiply parentheses ..

-((+x^2-1x-6x+6))+(x-4)^2=0



We calculate terms in parentheses: -((+x^2-1x-6x+6)), so:

(+x^2-1x-6x+6)

We get rid of parentheses

x^2-1x-6x+6

We add all the numbers together, and all the variables

x^2-7x+6

Back to the equation:

-(x^2-7x+6)



We get rid of parentheses

-x^2+7x+(x-4)^2-6=0

We add all the numbers together, and all the variables

-1x^2+7x+(x-4)^2-6=0

We move all terms containing x to the left, all other terms to the right

-1x^2+7x+(x-4)^2=6

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